Explanation:
It is given that,
Length of the rod, l = 14 cm = 0.14 m
Charge on the rod,
We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m
Electric field at the axis of the rod is given by :
Where
is the linear charge density of the rod,
E = -7493170.57 N/C
or
Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.
