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lianna [129]
3 years ago
6

Positive electric charge Q is distributed uniformly throughout the volume of an insulating sphere with radius R.From the express

ion for E=kQ/r2 for r>R and E=kQr/R3 for r
Only need C & D. It asks for specfic points that I don't know how to find. I just know the general shape of the graph.
Physics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

Vb = k Q / r        r <R

Vb = k q / R³ (R² - r²)    r >R

Explanation:

The electic potential is defined by

             ΔV = - ∫ E .ds

We calculate the potential in the line of the electric pipe, therefore the scalar product reduces the algebraic product

             VB - VA = - ∫ E dr

Let's substitute every equation they give us and we find out

r> R

           Va = - ∫ (k Q / r²) dr

           -Va = - k Q (- 1 / r)

We evaluate with it Va = 0 for r = infinity

          Vb = k Q / r        r <R

         

We perform the calculation of the power with the expression of the electric field that they give us

           Vb = - int (kQ / R3 r) dr

  We integrate and evaluate from the starting point r = R to the final point r <R

         Vb = ∫kq / R³ r dr

         Vb = k q / R³ (R² - r²)

This is the electric field in the whole space, the places of interest are r = 0, r = R and r = infinity

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aleksandr82 [10.1K]

Answer:

option (b)

Explanation:

Let the resistance of each resistor is R.

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Let V be the source of potential difference.

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Ps = v^2 / Rs = V^2 / NR ..... (1)

In parallel combination

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1 / Rp = N / R

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Power is parallel

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Divide equation (1) by equation (2) we get

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A rubber ball and a stone of the same size are examples which will have more inertia and is therefore denoted as option A.

<h3>What is Inertia?</h3>

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