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3 years ago

Please answer this soon. Thank u.

Physics

1 answer:

vodomira [7]3 years ago

6 0

Answer:

The distance used to calculate the pressure of atmosphere is 75 cm.

Explanation:

Mercury barometer is used to find the pressure of the atmosphere where it is placed.
As shown in the figure, the barometer has an inverted tube where mercury has risen by 75 cm. This height is taken into count to measure the atmospheric pressure.
At the place with high pressure the mercury in the inverted tube will go very high and vice versa.
Hence to find the pressure we must note down the height of mercury that has risen the inverted tube.

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As galáxias são maiores do que os enxames de estrelas?

GuDViN [60]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Responder \;\;a}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

As galáxias são geralmente maiores do que os aglomerados de estrelas. Como disse Geller ~ As galáxias são como as cidades em que vivem os aglomerados de estrelas. As galáxias podem ter cerca de milhares ou mais aglomerados de estrelas ~

I hope it helps ~

8 0

3 years ago

If the ball leaves the projectile launcher at a speed of 2.2 m/s at an angle of 30ᴼ, and the projectile launcher is on a table a

IgorC [24]

Answer: 1.12 m

Explanation:

This situation is related to parabolic motion, hence we can use the following equations:

$y=y_{o}+V_{o}sin \theta t-\frac{g}{2}t^{2}$ (1)

$x=V_{o} cos \theta t$ (2)

Where:

$y=0 m$ is the ball final height (when it hits the ground)

$y_{o}=1.1 m$ is the ball initial height

$V_{o}=2.2 m/s$ is the initial velocity

$\theta=30\°$ is the angle at which the ball was launched

$t$ is the time

$g=9.8 m/s^{2}$ is the acceleration due gravity

$x$ is the horizontal distance the ball travels

Rewriting (1) with the given values:

$0 m=1.1 m+(2.2 m/s)(cos 30\°)t-\frac{9.8 m/s^{2}}{2}t^{2}$ (3)

Multiplying all the eqquation by -1 and rearranging:

$4.9 m/s^{2} t^{2}-1.1 m/s t-1.1 m=0$ (4)

So, since we have a quadratic equation here (in the form of $0=at^{2}+bt+c$ , we will use the quadratic formula to find $t$ :

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ (5)

Where $a=4.9$ , $b=-1.1$ , $c=-1.1$

Substituting the known values and choosing the positive result of the equation, we have:

$t=\frac{-(-1.1)\pm\sqrt{(-1.1)^{2}-4(4.9)(-1.1)}}{2(4.9)}$

$t=0.59 s$ (6)

Now, substituting (6) in (2):

$x=(2.2 m/s)(cos 30\°)(0.59 s)$ (7)

$x=1.12 m$ (8) This is the horizontal distance at which the ball hits the ground.

3 0

4 years ago

Which one of these contains two carbon atoms and six hydrogen atoms

kondor19780726 [428]

The second option
You can see it in the name that see represents carbon and H represents hydrogen on the periodic table. The numbers after it are the amount of items that are in the molecule

7 0

3 years ago

Read 2 more answers

What is the natural pH of the ocean?

Katyanochek1 [597]

Answer: Basic

Explanation: water is "neutral" with a ph of 7, the ocean has like 8 so it is more basic on the scale

7 0

3 years ago

Read 2 more answers

A ladybug crawls vertically on a leaf. Its motion is shown on the following graph of vertical position y vs. time t. What is the

ella [17]

Answer: 0 m/s

Explanation: The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.

We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.

It means its velocity is equal to at this time or we can say that ladybug is at rest.

7 0

3 years ago