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Taya2010 [7]
2 years ago
9

Compare the fractions 2/5 to 3/4

Mathematics
2 answers:
anygoal [31]2 years ago
8 0
This is the answers

adelina 88 [10]2 years ago
4 0
2/5 is smaller than 3/4

If u do:

3/4 =.75

And 2/5= .4

Then add a 0 after the 4 to get .40

.40 < .75

2/5 < 3/4

Hope this helps!
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David made a table to relate two customary units. Label the columns of the table
tigry1 [53]
The customary unit is add 16 each time hope  i help 
5 0
2 years ago
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Haley solving this problem by combining like terms 3x +5x=10
GaryK [48]

Answer:

x = 5/4

Step-by-step explanation:

By combining like terms, you get 8x = 10.

Divide the 8 on both sides of the equation.

x = 10/8

This, however, can be simplified by dividing by 2. This ultimately gives us 5/4.

5 0
3 years ago
Read 2 more answers
I NEED HELP!!!
oksano4ka [1.4K]

Answer:

x= -2, y = -3

Step-by-step explanation:

1. substitute x = 4+2y in the first equation: \begin{bmatrix}2\left(4+2y\right)+y=-7\end{bmatrix}

simplify it : \begin{bmatrix}8+5y=-7\end{bmatrix}

2. isolate y in 8 + 5y = -7 --> 5y = -7 - 8 -->

3. solve for y:  5y = -15 --> y = -15/5 --> y= -3

4. solve for x: x = 4 + 2y

x = 4 + 2(-3)

x = 4 + (-6)

x = -2

6 0
2 years ago
Answers?? With work please
Naya [18.7K]
1.)-2
2)-2
3.)-3
4.)-1
5)1
6.)-6
7.)-6
8.)4
9.)0
10.)no solution
11.)-3
12.)all real numbers
13.)-1
14.)5
On working on the work for the first problem so u understand
7 0
3 years ago
Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2
Vsevolod [243]

Answer:

Given that:

a = (\frac{x+ip}{2})^{\frac{1}{2}} and a+= (\frac{x-ip}{2})^{\frac{1}{2}}

if a , a+ commutator, it obeys aa^+ = a^+a

First find:

aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}

                = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

Now;

a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}

              =(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}

therefore, aa^+ = a^+a which implies the operators a and a+ are commutators.    


7 0
3 years ago
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