Question

Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:

Answer 1

This question is incomplete. The complete question is given below:

Write a program that gets a single character from the user. If the character is not a capital letter (between 'A' and 'Z'), then the program does nothing. Otherwise, the program will print a triangle of characters that looks like this:

  A

 ABA

ABCBA

ABCDCBA

Answer:

#include <stdio.h>

void printTri(char asciiCharacter){

   // Row printer

//   for(int i = 65; i <= ((int)asciiCharacter); i++){

   int i = 65;

   while(i <= ((int)asciiCharacter)){

       int leftMargin = ((int)asciiCharacter) - i; +

       int j = 1;

       while(j <= leftMargin){

           printf(" ");

           j++;

       }

       int k = 65;

       while(k < ((int)i)){

           printf("%c",(char)k);

           k++;

       }

       int l = ((int)i);

       while(l >= 65){

           printf("%c",(char)l);

           l--;

       }

       printf("\n");

       i++;

   }

}

int main()

{

   for(;;){

       printf("Please enter a character between A and Z. Enter (!) to exit \n");

       char in;

//       scanf("%c",&in);

       in = getchar();

       getchar();

       printf("Printing Triangle for: %c \n",in);

       if(((int)in) >= 65 && ((int)in) <= 90){

           printTri(in);

           printf("\n");

       }else if(((int)in) == 33){

           break;

       } else {

           continue;

       }

   }

   return 0;

}

Explanation:

• Inside the printTri function, print spaces, characters in order as well as characters in reverse order.
• Inside the main function, take the character as an input from user then print the triangle by validating first to ensure that the character lies between a to z alphabets.