HELPPP PLSSS
2 answers:
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<h2><u>Answer with explanation</u>:</h2>
Let be the population mean.
As per given , we have
Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given , so we perform one-tailed z-test.
Test statistic :
, where = Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 , ,
,
, we have
P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
Answer:
<u>Group the Variable's</u>:
2 x - 5 + 7 y - 3 = 9 x - 1 - y -8
2x -9x + 7y +y = -1 -8 +5 + 3
-7x + 8y = -1
<u><em>From this find x and y</em></u>
<u>For X</u>
-7x + 8y = -1
-7x = -1 -8y
7x = 8y + 1
x = (8y +1)/7
<u>For Y</u>
-7x + 8y = -1
8y = -1 +7x
y = (7x -1)/8