All categories

4 years ago

20 POINTS!!QUESTION ATTATCHED PLEASE HURRY

Mathematics

1 answer:

Step2247 [10]4 years ago

3 0

Answer:

I believe it is the second answer.

You might be interested in

13. Imagine that you are taking a class and your chances of being asked a question in class are 1% during the first week of clas

liberstina [14]

Answer: There is probability that he will be asked a question in class during Week 7 is 64%.

Step-by-step explanation:

Since we have given that

Probability that question in class being asked during Week 1 = 1%

Probability that question in class being asked during Week 2 = 2%

Probability that question in class being asked during Week 3 = 4%

and so on.

So, we need to find the probability that question being asked in class during week 7.

Since it forms geometric series:

1%, 2%, 4%, ........

So, we need to find the 7 th term:

$a_n=ar^{n-1}\\\\a_7=ar^{7-1}\\\\a_7=1(2)^6\\\\a_7=64\%$

Hence, there is probability that he will be asked a question in class during Week 7 is 64%.

8 0

4 years ago

What is the answer please 2(4 + 2z) =

Alika [10]

Answer: It would be 8+4z because you can't add a variable.

4 0

3 years ago

Read 2 more answers

Find the coordinates of the midpoint of a segment having the given endpoints.

BartSMP [9]

X² + x¹ 11+1
--------- =. ------= 6
2. 2

y² + y¹. 5+(-3).
-------- = ---------- = 1
2. 2

So the midpoint is a) (6,1)

3 0

3 years ago

Read 2 more answers

Can someone help? explanations appreciated!

Kazeer [188]

The answer is 9/25 just look for values.

3 0

2 years ago

Calculate the perimeter of a triangle whose dimensions are 1m 60cm, 1m 80cm and 2m.

Tatiana [17]

★ AnsWer :

➨ 540 cm

★ Step by step Explaination :

Let triangle be ABC,

1m = 100 cm

$\begin{lgathered}\bullet\:\:\textsf{AB = 1m 60cm = \textbf{160 cm}}\\\bullet\:\:\textsf{BC = 1m 80cm = \textbf{180 cm}}\\\bullet\:\:\textsf{CA = 2m = \textbf{200 cm}}\end{lgathered}$

$\setlength{\unitlength}{1.5cm}\begin{picture}(6,8)\linethickness{0.5mm}\qbezier(1,.5)(2,1)(4,2)\qbezier(4,2)(2,3)(2,3)\qbezier(2,3)(2,3)(1,0.5)\put(.7, .3){$C$}\put(4.05, 1.9){$B$}\put(1.7, 2.95){$A$}\put(3.2, 2.5){\sf{160 cm}}\put(0.7,1.7){\sf{200 cm}}\put(2.7, 1.05){\sf{180 cm}}\end{picture}$

$\rule{130}1$

$\underline{ \large \purple{ \mathscr{\dag\:A \bf{ccording} \: to \: \mathscr {Q} \bf{uestion} ....}}}$

$\begin{lgathered}\dashrightarrow\tt\:\: Perimeter_{{\tiny\triangle ABC}}=Sum\:of\:all\:sides\\\\\\\dashrightarrow\tt\:\: Perimeter_{{\tiny\triangle ABC}} = AB + BC + CA\\\\\\\dashrightarrow\tt\:\: Perimeter_{{\tiny\triangle ABC}} = 160 + 180 + 200\\\\\\\dashrightarrow\:\:\underline{\boxed{\tt Perimeter_{{\tiny\triangle ABC}} = 540 \:cm}}\end{lgathered}$

$\therefore\:\underline{\textsf{Perimeter of triangle ABC is \textbf{540 cm}}}.$

8 0

3 years ago

Read 2 more answers