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4 years ago

Design a sequential circuit with two D flip-flops A and B, and one input x_in.

Engineering

1 answer:

DENIUS [597]4 years ago

7 0

Answer:

View Image

Explanation:

The question is basically asking you to build a 2-bit asynchronous counter.

What the counter does is it increase it's value by 01₂ every clock pulse. So at 0₂, nothing happens, but at 1₂ it'll count up by 1. It then reset to 00₂ when it overflows.

The design for it is pretty much universal so I kinda did this from memory.

a.) A count-up counter (from 00-11) is simply made by connecting Q' to D, and the output of the previous DFF to the clock of the next one.

b.) A count-down counter (from 11-00) is simply made by using the same circuit as the count-up counter, but you connect Q' to the clock instead of Q.

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Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

string studentFName;

string studentLName;

int testScore;

char grade;

};

void readStudentData(StudentType students[]){

int i = 0;

ifstream infile;

infile.open("inputStudentData.txt");

while (!infile.eof())

{

infile >> students[i].studentFName;

infile >> students[i].studentLName;

infile >> students[i].testScore;

students[i].grade = getStudentGrade(students[i].testScore);

i++;

}

char getStudentGrade(int testScore){

char grade;

if(testScore >= 80) {

grade = 'A';

}

else if(testScore >= 60) {

grade = 'B';

}

else if(testScore >= 50) {

grade = 'C';

}

else if(testScore >= 40) {

grade = 'D';

}

else {

grade = 'F';

}

return grade;

}

int main()

{

StudentType students[10];

readStudentData(students);

for(int i=0;i<maxStudents;i++) {

students[i].grade = getStudentGrade(students[i].testScore);

}

for(int i=0; i<maxStudents; i++){

cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

ofstream outputFile;

outputFile.open ("outputStudentData.txt");

for(int i=0; i<maxStudents; i++){

outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

outputFile.close();

return 0;

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4 years ago

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3 years ago

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Answer:

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Explanation:

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Answer:

Explanation:

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