To check for ripple voltage from the alternator, connect a digital multimeter and select

Design circuits that demonstrate all of the principles listed below. Set up the circuits and take measurements to show that the

Nata [24]

<u>Explanation</u>:

For series

$\Delta V=V_{1}+V_{2}+\ldots+V_{n}=I R_{1}+I R_{2}+\ldots+I R_{n}(\text {voltages add to the batter } y)$

$$I=I_{1}=I_{2}=I_{n}$ (current is the same)$

$V=I R(\text {voltage is directly proportional to } R)$

$R_{e q}=R_{1}+R_{2}+\ldots+R_{n} \quad \text { (resistance increase) }$

For parallel

$\Delta V=\Delta V_{1}=\Delta V_{2}=\Delta V_{n} \quad(\text { same voltage })$

$I=I_{1}+I_{2}+\ldots+I_{n}(\text {current adds})$

$I=\frac{\Delta V}{R_{e q}} \quad(R \text { inversal } y \text { proportional to } I)$

$\frac{1}{R_{e q}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\ldots+\frac{1}{R_{n}}$

3 0

3 years ago

A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below: Depth (m) Con

Cerrena [4.2K]

Answer:

hello your question is incomplete attached below is the missing equation related to the question

answer : 40.389° , 38.987° , 38° , 39.869° , 40.265°

Explanation:

<u>Determine the friction angle at each depth</u>

attached below is the detailed solution

To calculate the vertical stress = depth * unit weight of sand

also inverse of Tan = Tan^-1

also qc is in Mpa while σ0 is in kPa

Friction angle at each depth

2 meters = 40.389°

3.5 meters = 38.987°

5 meters = 38.022°

6.5 meters = 39.869°

8 meters = 40.265°

6 0

3 years ago

What is an advantage of using a fully integrated cloud-based data analytics platform?

sweet [91]

Answer:

It gives decision-makers the processing capacity they need to turn raw data into useful knowledge.

Explanation:

Data analysis and the associated cycles (data integration, aggregation, hoarding, and revealing) are totally or partially directed in the cloud with cloud analytics.

3 0

2 years ago

Anyone want to play among us with me the code is MMJSUF

Katarina [22]

Answer:

sure

Explanation:

6 0

3 years ago

Read 2 more answers

The pilot of an airplane reads the altitude 6400 m and the absolute pressure 45 kPa when flying over the city. Calculate the loc

garri49 [273]

Answer:

1) The absolute pressure equals = 96.98 kPa

2) Absolute pressure in terms of column of mercury equals 727 mmHg.

Explanation:

using the equation of pressure statics we have

$P(h)=P_{surface}-\rho gh...............(i)$

Now since it is given that at 6400 meters pressure equals 45 kPa absolute hence from equation 'i' we obtain

$P_{surface}=P(h)+\rho gh$

Applying values we get

$P_{surface}=45\times 10^{3}+0.828\times 9.81\times 6400$

$P_{surface}=96.98\times 10^{3}Pa=96.98kPa$

Now the pressure in terms of head of mercury is given by

$h_{Hg}=\frac{P}{\rho _{Hg}\times g}$

Applying values we get

$h=\frac{96.98\times 10^{3}}{13600\times 9.81}=0.727m=727mmHg$

7 0

3 years ago