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1 year ago

What is an automotive system in relation to a vehicle’s structure and operation?

2 answers:

7 0

Answer:

Automotive System. A group of related parts that perform a specific function. Body and Chassis System. Body, frame, suspension, steering, braking which support, stop and enclose the parts of the car.

andrew11 [14]1 year ago

3 0

Answer:

Automotive System. A group of related parts that perform a specific function. Body and Chassis System. Body, frame, suspension, steering, and braking support, stop and enclose the car parts.

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Can be used to eliminate rubbing friction of wheel touching frame. 1.Traction 2.Thrust washer

Vilka [71]

Answer:

thrust washer

can be used to eliminate rubbing friction of wheel touching frame

5 0

3 years ago

The ratio of boys to girls in the class was 2 to 3. If there were 18 girls in the class, how many students were in the class

iren2701 [21]

37 students in the class
18 Girls and 19 Boys

4 0

3 years ago

Using the data in the photo write the complex waveform expression

UNO [17]

Answer:

1st Harmonic:

$v(t) = 50\cos(2000\pi t)$

3rd Harmonic:

$v(t) = 9\cos(6000\pi t)$

5th Harmonic:

$v(t) = 6\cos(10000\pi t)$

7th Harmonic:

$v(t) = 2\cos(14000\pi t)$

Explanation:

The general form to represent a complex sinusoidal waveform is given by

$v(t) = A\cos(2\pi f t + \phi)$

Where A is the amplitude in volts of the sinusoidal waveform

Where f is the frequency in cycles per second (Hz) of the sinusoidal waveform

Where $\phi$ is the phase angle in radians of the sinusoidal waveform.

1st Harmonic:

We have A = 50, f = 1000 and φ = 0

$v(t) = 50\cos(2\pi 1000 t + 0) \\\\v(t) = 50\cos(2000\pi t)$

3rd Harmonic:

We have A = 9, f = 3000 and φ = 0

$v(t) = 9\cos(2\pi 3000 t + 0) \\\\v(t) = 9\cos(6000\pi t)$

5th Harmonic:

We have A = 6, f = 5000 and φ = 0

$v(t) = 6\cos(2\pi 5000 t + 0) \\\\v(t) = 6\cos(10000\pi t)$

7th Harmonic:

We have A = 2, f = 7000 and φ = 0

$v(t) = 2\cos(2\pi 7000 t + 0) \\\\v(t) = 2\cos(14000\pi t)$

Note: The even-numbered harmonics have 0 amplitude that is why they are not shown here.

8 0

4 years ago

Read 2 more answers

Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale

artcher [175]

The composition of gas in the feed, the percentage conversion and the

theoretical yield are combined to give the product stream composition.

Response:

The composition of gas in the product stream are;

HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/h

<h3>How can percentage conversion give the contents of the product stream?</h3>

The amount of oxygen used = 30% exceeding the theoretical amount

Number of moles of hydrochloric acid = 4 kmol/h

Percentage conversion = 80%

Required:

The composition of the gas in the product feed.

Solution;

The given reaction is; 4HCl + O₂ $\longrightarrow$ 2Cl₂ + 2H₂O

$Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \ of \ limiting \ reactant \ supplied \ in \ the \, feed}}$

Which gives;

$80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}$

Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h

Which gives;

Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h

Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Similarly;

Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h

The composition of the production stream is therefore;

<u>HCl: 0.4 kmol/h</u>

<u>Cl₂: 1.6 kmol/h</u>

<u>H₂O: 1.6 kmol/h</u>

<u>O₂: 0.5 kmol/h</u>

Learn more about theoretical and actual yield here:

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3 years ago

A worker is transporting dirt using a wheelbarrow. The handle is four feet long, the distance from the center of the wheelbarrow

Margarita [4]

Answer:

ewjerhkj

Explanation:

gkkgkjgfe

7 0

3 years ago