One machines value changed by -$6400 over 5 years. THe company charges off such changes in value as depreciation. Each year an e
qual amount is charged off. What was the change in value that would be charged off each year for this machine?
1 answer:
This problem ends up being a simple division problem.
If the machine's value went down 6400 in 5 years, you just have to divide 6400 by 5 to find the value lost per year.
6400 / 5 years = 1280 / year
Each year, $1280 would be charged off.
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Use the formula:
![A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}](https://tex.z-dn.net/?f=A%28x_A%3B%5C%20y_A%29%3B%5C%20B%28x_B%3B%5C%20y_B%29%5C%5C%5C%5C%7CAB%7C%3D%5Csqrt%7B%28x_B-x_A%29%5E2%2B%28y_B-y_A%29%5E2%7D)
We have:
![A(-2;\ -3);\ B(-4;\ 4)](https://tex.z-dn.net/?f=A%28-2%3B%5C%20-3%29%3B%5C%20B%28-4%3B%5C%204%29)
substitute:
Answer:
Since 4x is only the radius then you.
4x+4x= 8x then set them equal to each other.
2x + 12 = 8x
-2x
12 = 6x
divide by 6
2 = x
well, BC is in Canada and is 1/11.
Vancouver is in BC and is 1/29 of BC.
so Vancouver is then 1/29 of 1/11, how much is that? well, is simply their product.
![\bf \cfrac{1}{29}\cdot \cfrac{1}{11}\implies \cfrac{1}{319}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B1%7D%7B29%7D%5Ccdot%20%5Ccfrac%7B1%7D%7B11%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B319%7D)
Answer:
12-10=2 / (6×5)=30 / 5×2=10 / 12×2=24 / 6+5-2=9
Answer:.01
Step-by-step explanation: