Question

What is the surface area of this triangular prism rounded to the nearest tenth?

Answer 1

Answer:

B. 145.3 ft2

Step-by-step explanations:

Answer 2

Answer:

The surface area of the triangular prism is $145.3$  $ft^2$

Step-by-step explanation:

Step 1:  Finding the two area of two triangles

Area of the triangle  =  $\frac{1}{2} (base \times height})$

Area of the triangle  = $\frac{1}{2} (9.8\times 5.33})$

Area of the triangle  = 26.117

Area of 2 triangles  =  $52.234$

Step 2: Finding the area of the side rectangles

Area of the rectangle  = $length \times breadth$

Area of the rectangle  1 = $6.2 \times 3.8$  = 23.56 $ft^2$

Area of the rectangle  2  = $8.5 \times 3.8$ = 32.3 $ft^2$

Area of the rectangle  3  = $9.8 \times 3.8$ = 37.24 $ft^2$

Step 3: surface area of the triangular prism.

Surface area of the triangular prism =  52.234 + 23.56 + 32.3 + 37.24

Surface area of the triangular prism = 145.334 $ft^2$