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3 years ago

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Which of the following is a conjugate for 7 + i Square root of 2? (2 points) − 7 + i Square root of 2 7 − i Square root of 2 i S

quare root of 2 + 7 −i Square root of 2 − 7

1 answer:

hammer [34]3 years ago

3 0

Answer:

$7-\sqrt{2}i$

Step-by-step explanation:

Given number is $7+\sqrt{2}i$ . We need to find the complex conjugate of the given number.

We will use the general rule to find out the complex conjugate of the number.

The complex conjugate of $a+bi$ will be $a-bi$

And the complex conjugate of $7+\sqrt{2}i\ became\ 7-\sqrt{2}i$

So, the complex conjugate of $7+\sqrt{2}i$ is $7-\sqrt{2}i$

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Which of the following fractions is less than 1<br> options: a) 1 1by4 b) 3/4 c) 5/4 d) 2 3by4

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What is the sum or difference?

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1. Ans: Option (B) $-6x^4$

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Given: $2x^4 - 8x^4$
Take the common out:
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2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ <span> quadratic trinomial

Explanation:
</span>Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: $3.1x^2 +6.0x + 0.3$ <span>
Endler's guppies: </span> $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

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