Answer:
#1: 11 cm
#2: 16.5 in
#3: 2.5 feet
Step-by-step explanation:
#1
Solve for width by substracting 2l on both sides to isolate 2w
or
Replace.
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#2
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#3
Solve for l
Answer:
The probability is
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
Answer: b. Only statement (ii) is correct.
Step-by-step explanation:
The given five-number summary of the ages of passengers on a cruise ship is listed below.
Min 1 20 Median 29
38 Max 80
Inter-quartile range =
Here ,
Since the minimum value> ( ∵ 1 > -7)
It means there is no value below , so there is no low -outlier.
⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.
But the maximum value > (∵ 85 > 65)
It means there are values above .
⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.
Hence, the correct answer is b. Only statement (ii) is correct.