Using the quadratic equation x2-3x+2=0 perform the following tasks:

1 answer:

8 0

$x^2-3x+2=0\\
x^2-x-2x+2=0\\
x(x-1)-2(x-1)=0\\
(x-2)(x-1)=0\\
x=2 \vee x=1\\\\\
x^2-3x+2=0\\
x^2-3x+\frac{9}{4}-\frac{1}{4}=0\\
(x-\frac{3}{2})^2=\frac{1}{4}\\
x-\frac{3}{2}=\sqrt{\frac{1}{4}} \vee x-\frac{3}{2}=-\sqrt{\frac{1}{4}}\\
x-\frac{3}{2}=\frac{1}{2} \vee x-\frac{3}{2}=-\frac{1}{2}\\
x=\frac{4}{2} \vee x=\frac{2}{2}\\
x=2 \vee x=1$

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Find the value of a. A. 58 B. 130 C. 86 D. 65

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Answer:

$C. \ \ \ 86$ °

Step-by-step explanation:

1. Approach

In order to solve this problem, one must first find a relationship between arc (a) and arc (c). This can be done using the congruent arcs cut congruent segments theorem. After doing so, one can then use the secants interior angle to find the precise measurement of arc (a).

2. Arc (a) and arc (c)

A secant is a line or line segment that intersects a circle in two places. The congruent segments cut congruent arcs theorem states that when two secants are congruent, meaning the part of the secant that is within the circle is congruent to another part of a secant that is within that same circle, the arcs surrounding the congruent secants are congruent. Applying this theorem to the given situation, one can state the following:

$a = c$

3. Finding the degree measure of arc (a),

The secants interior angle theorem states that when two secants intersect inside of a circle, the measure of any of the angles formed is equal to half of the sum of the arcs surrounding the angles. One can apply this here by stating the following:

$86=\frac{a+c}{2}$