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kramer
3 years ago
10

Which correctly shows the process of photosynthesis?

Biology
1 answer:
Elenna [48]3 years ago
3 0
Number four would be correct - ♡
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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
IgorLugansk [536]

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
2 years ago
At the start of the lab, you will test known samples in order to see what positive and negative test results look
son4ous [18]

Answer:

I feel it's to easily differentiate the positive from the negative...... like in gram staining of bacteria, the colour tell us which bacteria is gram positive or gram negative...... I just feel that this is science and it is advisable to know what the opposite result of an experiment should look like.

8 0
2 years ago
Which complex carbohydrate contains only a-1,4-glycosidic linkages?
Andrei [34K]

Answer: Amylose

Explanation: Which complex carbohydrate contains only a-1,4-glycosidic linkages? Amylose (Amylose is formed from a-1,4-glycosidic linkages of glucose.)

5 0
3 years ago
A system that allows pharmacists to automatically substitute with certain pharmacologic or therapeutic alternatives without call
sp2606 [1]

A system that allows pharmacists to automatically substitute with certain pharmacologic or therapeutic alternatives without calling the prescriber each time is known as a Therapeutic interchange.

Therapeutic interchange is the practice of replacing, with the prescribing practitioner's approval, a prescription medication originally prescribed for a patient with an alternative prescription medication. Therapeutic drug monitoring (TDM) is testing that measures the amount of certain medicines in your blood. It is done to make sure the amount of medicine you are taking is both safe and effective.

Therapeutic drug monitoring helps in designing patient-specific dosage regimen, it aids in enhancing the efficacy of drugs, to reduce the toxicity of drugs and for diagnostic purposes, by individualizing drug therapy.

To learn more about Therapeutic interchange , here

brainly.com/question/2141502

#SPJ4

4 0
1 year ago
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