Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / 
~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
They acknowledge the source of a quotation, paraphrase, or summary; and (2) They provide explanatory comments that would interrupt the flow of the main text.so its B
<span>It is generally a good idea to set the font size to at least 30 points in presentations </span><span>to ensure readability even from a distance.</span>
Are you trying to change the shape of an item within your program by entering the values into text boxes that become variables?
What language are you using?
Answer:
Explanation:
a. In this scenario, the best solution would have an Object of Traditional Books, CD, Music, Bookstore and Customer.
b. All five objects would be able to be called by the main program loop and the Customer Object would call upon and use either the Books or CD object, While the Bookstore object would call upon all of the other objects.
c. Both the Bookstore object and Customer object will "have" other objects as the Bookstore needs to hold information on every Book or CD in the Inventory. While the Customer object would call upon the Book and CD object that they are purchasing.
d. The Music Object will extend the CD object and use information on the CD object as its parent class.
e. Since the Music Object extends the CD object it is also considered a CD since it is in CD format like the Books on CD and therefore is both objects.
