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Alex777 [14]
3 years ago
10

Find the solutions to the equation below, Check all that apply. 16x^2-64=0

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
5 0
<h2>Answer:</h2>

The solution of the given equation is:

          x=2 and x= -2

<h2>Step-by-step explanation:</h2>

We are given an quadratic equation as:

                            16x^2-64=0

Now we are asked to find the solution of this equation i.e. we are asked to find the possible value of x that satisfy this equation.

        16x^2-64=0\\\\\\16(x^2-4)=0\\\\\\x^2-4=0\\\\(x-2)(x+2)=0

Since, we know that:

a^2-b^2=(a-b)(a+b)

Hence, we have:

x=2 or x= -2

     Hence, the solution of the equation are:

                                    2 or -2.

Ivan3 years ago
4 0
X= 2, -2 is the answer
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