Question

Find the solutions to the equation below, Check all that apply. 16x^2-64=0

Answer 1

Answer:

The solution of the given equation is:

          x=2 and x= -2

Step-by-step explanation:

We are given an quadratic equation as:

                            $16x^2-64=0$

Now we are asked to find the solution of this equation i.e. we are asked to find the possible value of x that satisfy this equation.

        $16x^2-64=0\\\\\\16(x^2-4)=0\\\\\\x^2-4=0\\\\(x-2)(x+2)=0$

Since, we know that:

$a^2-b^2=(a-b)(a+b)$

Hence, we have:

x=2 or x= -2

     Hence, the solution of the equation are:

                                    2 or -2.

Answer 2

X= 2, -2 is the answer