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IceJOKER [234]
3 years ago
8

A designer creates a drawing of a triangular sign on centimeter grid paper for a new business. The drawing has sides measuring 6

cm 8cm and 10cm and the angles measuring 37 53 and 90 degrease find the length of the side of its actual sign
Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0
The actual length is 6*40=240 cm, 8*40=320 cm, 10*40=400 cm. And the angle measures of the actual sign will not change. The transformation can be turning over using the hypotenuse as axle. Or rotate the triangular sign 180° using the center of the triangle as the center of rotation. The turning over method will accomplish.

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Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

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Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

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0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

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