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DochEvi [55]
3 years ago
5

Steve drives at a constant speed of 59.3 mph. How far should he expect to drive in 7/8 hr?

Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

51.9 miles

Step-by-step explanation:

distance  = speed * time

d = 59.3 * 7/8

d = 51.8875 miles

rounded

51.9 miles

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xenn [34]

Answer:

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(b) 12.92

Step-by-step explanation:

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                A = Pe^{rt}

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

               A = 2 × $3000

               A = $6000

               6000 = 3000e^{0.085t}

               \frac{6000}{3000} = e^{0.085t}

               2 = e^{0.085t}

Take log_{e} of both sides

               log_{e}2 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln2 = 0.085t

               t = \frac{ln2}{0.085}

               t = \frac{0.693}{0.085}

               t = 8.15

(b) For the amount to double, A = 3 × P

               A = 3 × $3000

               A = $9000

               9000 = 3000e^{0.085t}

               \frac{9000}{3000} = e^{0.085t}

               3 = e^{0.085t}

Take log_{e} of both sides

               log_{e}3 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln3 = 0.085t

               t = \frac{ln3}{0.085}

               t = \frac{1.0986}{0.085}

               t = 12.92

5 0
3 years ago
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Paraphin [41]
2/3 and 12/18 are equivalent fractions, and 12+18 = 30 so the answer is 12:18 
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