It would be, 33%.
Hope this helps!

(a)
![f'(x) = \frac{d}{dx}[\frac{lnx}{x}]](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Cfrac%7Blnx%7D%7Bx%7D%5D)
Using the quotient rule:


For maximum, f'(x) = 0;


(b) <em>Deduce:
</em>

<em>
Soln:</em> Since x = e is the greatest value, then f(e) ≥ f(x) > f(0)


, since ln(e) is simply equal to 1
Now, since x > 0, then we don't have to worry about flipping the signs when multiplying by x.



Taking the exponential to both sides will cancel with the natural logarithmic function in the right hand side to produce:


, as required.
Answer:If it has 4 equal sides
If the angles are 90°
Hope this may helps you
im in middle school taking algebra 1 rn, but im pretty sure the equation is similar to 40x(40 pledges every mile) + 250(how much he already has from running) = y(the unknown variable).
so the equation would be 40x+250=y and you solve that to get the expression of how much he makes per mile
Example of integers are -5 ,1 ,5 , 8 , 97 and 3,043