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Travka [436]
3 years ago
7

Why is there no electric field at the center of a charged spherical conductor?

Physics
1 answer:
Svetlanka [38]3 years ago
4 0
-- Since the sphere is a conductor, the charge on it will move around
until it's evenly distributed on the surface of the sphere.  When every
tiny smitch of charge is the same distance from the charge around it,
they won't need to move around any more.

-- At that point, the situation at the center of the sphere will be:
For every smitch of charge on the surface, causing en electric field
at the center, there is another smitch, of the same size and in exactly
the opposite direction, canceling out the field of the first one. 
Every smitch of charge on the surface causes a tiny bit of electric field
at the center, and they all cancel each other.

It turn out that if the sphere is hollow, then the electric field at EVERY
point inside it is zero, not only at the center.

It's exactly the same idea as a sphere with uniform, homogeneous mass.
For that sphere, the gravity at the center is zero.
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Answer:

<h2>50 N</h2>

Explanation:

The force required can be found by using the formula

f =  \frac{w}{d}  \\

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From the question we have

f =  \frac{25}{0.5}  \\

We have the final answer as

<h3>50 N</h3>

Hope this helps you

6 0
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D

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Maybe your question is meant to be: which is not a wedge, because wedge is a combination of two inclined planes, use to separate bodies which are held together by large forces. Option A,B & C are all wedge except D.

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A car accelerates from rest to 90m/s in 3 seconds. What is the acceleration and how far did it travel?
Inessa [10]

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The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente
Gennadij [26K]

Answer:

18.1 × 10⁻⁶ A = 18.1 μA

Explanation:

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Since J(r) = Br, in the cylindrical wire. With width of 10.0 μm, dr = 10.0 μm. r = 1.20 mm. We have a differential current dI. We integrate first by integrating dθ from θ = 0 to θ = 2π.

So, dI = J(r)rdrdθ

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3 0
3 years ago
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