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Travka [436]
3 years ago
7

Why is there no electric field at the center of a charged spherical conductor?

Physics
1 answer:
Svetlanka [38]3 years ago
4 0
-- Since the sphere is a conductor, the charge on it will move around
until it's evenly distributed on the surface of the sphere.  When every
tiny smitch of charge is the same distance from the charge around it,
they won't need to move around any more.

-- At that point, the situation at the center of the sphere will be:
For every smitch of charge on the surface, causing en electric field
at the center, there is another smitch, of the same size and in exactly
the opposite direction, canceling out the field of the first one. 
Every smitch of charge on the surface causes a tiny bit of electric field
at the center, and they all cancel each other.

It turn out that if the sphere is hollow, then the electric field at EVERY
point inside it is zero, not only at the center.

It's exactly the same idea as a sphere with uniform, homogeneous mass.
For that sphere, the gravity at the center is zero.
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just olya [345]

Answer:

a=2.5\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

Solving the equation for a:

\displaystyle a=\frac{v_f-v_o}{t}

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\displaystyle a=\frac{7.5-0}{3}

\boxed{a=2.5\ m/s^2}

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Explanation:

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3 years ago
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Answer:

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Explanation:

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Answer:

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Potassium hydroxide (KOH) and hydrochloric acid (HCl) react in a beaker. They form potassium chloride (KCl) and water (H2O). Wha
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Potassium hydroxide (KOH) and hydrochloric acid (HCl) react in a beaker. They form potassium chloride (KCl) and water (H2O). This type of reaction is a double replacement reaction wherein the two principal reactants exchange after the reaction. The Cl will combine to the K forming KCl and the H will add to the OH forming H2O.

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