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Bumek [7]
3 years ago
6

A Ferris wheel, rotating initially at an angular speed of 0.500 rad/s, accelerates over a 7.00-s interval at a rate of 0.040 0 r

ad/s2 . What angular displacement does the Ferris wheel undergo in this 7-s interval? a. 4.48 rad b. 2.50 rad c. 3.00 rad d. 0.500 rad
Physics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

Angular displacement will be 4.48 rad

So option (a) will be correct option

Explanation:

We have given initial angular acceleration \omega _i=0.5rad/sec

Angular acceleration \alpha =0.04rad/sec^2

Time t = 7 sec

We have to find the angular displacement

We know that angular displacement is given by

\Theta =\omega _it+\frac{1}{2}\alpha t^2=0.5\times 7+\frac{1}{2}\times 0.04\times 7^2=4.48rad

So option (a) will be correct option

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4 0
3 years ago
What's the formula to find out power
Julli [10]

In general, 

                 Power = (energy moved) / (time to move the energy) .

If it's mechanical power, then     

                 Power = (work done) / (time to do the work) .

If it's electrical power, then it can be any one of these:

                 Power  =  (volts)  x  (amperes)

                 Power  =  (volts)²  /  (resistance, ohms)

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Whatever kind of energy you're dealing with, power always
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                  (amount of energy produced, used, or moved)
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3 0
3 years ago
Referring to the above diagram, how high will the ball rise on the right-hand incline?
Marina CMI [18]
I think it’s 15cm
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3 0
3 years ago
a 5.0 charge is placed at the 0 cm mark of a meterstick and a -4.0 charge is placed at the 50 cm mark. what is the electric fiel
Lesechka [4]

Answer:

-1748*10^N/C

Explanation:

See attached file

8 0
3 years ago
A projectile is launched into the air with the initial speed of vi = 40 m/s at a launch angle of 20 degrees above the horizontal
Sphinxa [80]

The range of the projectile is 188 m

Explanation:

The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

The path of a projectile is the combination of these two motions: see figure in attachment.

In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.

We have:

t = 5.0 s (time of fligth of the projectile)

and the horizontal velocity is constant, and it is given by

v_x = v_i cos \theta

where

v_i = 40 m/s is the initial velocity

\theta=20^{\circ} is the angle of projection

Substituting,

v_x = (40)(cos 20^{\circ})=37.6 m/s

And therefore, the range of the projectile is:

d=v_x t = (37.6)(5.0)=188 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

5 0
3 years ago
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