Question

(b) The mass of a single molybdenum atom is 1.59×10-22 g. Suppose enough Mo atoms were lined up like beads on a string to span a distance of 33.4 cm ( 13 inches). How many atoms would be required? atoms

Answer 1

Answer:N=1151724138 atoms

Explanation:The atomic radius of molybdenum atom is 145 picometers so lining up molybdenum atoms is like lining up the beads of radius 145 picometers

so one bead would cover the length of 145*2=290 picometers

hence the atom's diameter =D=290 picometers

D=290 *10^(-12)

$D=290/1000000000000$

also

Distance span= 33.4 cm

Distance span= 0.334m

As the Distance span adds up with no of atoms the resulting formula is

Distance span by atoms= No of atoms * atom's diameter

so

$N=\frac{Distance Spaned}{Atom's Diameter } \\N=0.334/(0.000000000290)\\N=1151724138 atoms$