Answer:
B. LZAQD
A. Younger than A but older than Q
Explanation:
To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.
- According to the law of superposition, in an undeformed sequence of strata, the oldest layer is always at the bottom and the youngest on top.
- In this case, we have a little disturbance but it did not affect much of the original bedding.
- So, the rock ages from L to Z to A to Q and D. L is the oldest and D is the youngest.
According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.
The unit of measurement for weight is that of force, which in the International System of Units (SI) is the newton. For example, an object with a mass of one kilogram has a weight of about 9.8 newtons on the surface of the Earth, and about one-sixth as much on the Moon.
The volume that will react with methane is 72.24dm3
Answer:
The new pressure of the gas is 57.69atm
Explanation:
P1 = 50 atm
T1 = 390K
T2 = 450K
P2 = ?
This problem requires pressure law.
Pressure law states that the pressure of a fixed mass of gas is directly proportional to its temperature provided volume remains constant.
Mathematically,
P = kT, k = P / T
P1 / T1 = P2 / T2 = P3 / T3 .......Pn /Tn
P1 / T1 = P2 / T2
Solve for P2,
P2 = (P1 * T2) / T1
P2 = (50 * 450) / 390
P2 = 57.69atm
The new pressure of the gas is 57.69atm