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Anni [7]
2 years ago
10

Explain the effect of change in concentration of a system in Equilibrium with at least one example.

Chemistry
1 answer:
Luda [366]2 years ago
3 0

Explanation:

If the concentration of a substance is changed, the equilibrium will shift to minimise the effect of that change. If the concentration of a reactant is increased the equilibrium will shift in the direction of the reaction that uses the reactants, so that the reactant concentration decreases. For example, decreased volume and therefore increased concentration of both reactants and products for the following reaction at equilibrium will shift the system toward more products.

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Which earth sphere does the following image most clearly represent
Alona [7]
The correct answer for this question is this one: "D. Hydrosphere"

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Hope this helps answer your question and have a nice day ahead.
4 0
3 years ago
Define density and mass
KengaRu [80]

<u>density</u> is a measure of mass per volume. <u>mass</u> is both a property of a physical body and a measure of its resistance to acceleration.

<em>hope this helps! ❤ from peachimin</em>

6 0
3 years ago
Space shuttle tiles, sandstone, and the glass in quartz halogen lamps are all made out of the same stuff: silicon dioxide. Why d
tankabanditka [31]

Answer:

Explained

Explanation:

The bond angle between the Si-O-Si is 145° .But this can also vary between 100° and 170°,  It is because of which the changes in properties is happening. Bond angles can affect the hybridization, lone pair repulsion and electronegativity.

Thus , Space shuttle tiles, sandstone, and the glass in quartz have different properties and are used according to their property.

5 0
3 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
3 years ago
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