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4 years ago

What would be the total voltage for the following battery configurations.

Physics

1 answer:

ohaa [14]4 years ago

4 0

Explanation:

If we're talking about li-ion batteries with a capacity of 3.6V, then the total voltages for each configuration would be:

1) 10.8V (3.6x4) Connected in series.

2) 7.2V (3.6x2) The opposing battery's voltage doesn't add.

3 ) 3.V Connected in parallel.

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When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele

algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be $2.238\times 10^{-19}j$

Explanation:

In first case wavelength of electromagnetic radiation $\lambda =480nm=480\times 10^{-9}m$

Plank's constant $h=6.6\times 10^{-34}J-s$

Maximum kinetic energy = 0.54 eV

Energy is given by $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J$

We know that energy is given

$E=K_{MAX}+\Phi$ , here $\Phi$ is work function

So $4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi$

$\Phi =3.585\times 10^{-19}J$

Now wavelength of second radiation = 340 nm

So energy $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J$

So $K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j$

6 0

4 years ago

A roller coaster needs to climb a tall hill. How tall of a hill can it climb with an initial

iren [92.7K]

Answer:

h = 11.25m

Explanation:

mgh = 1/2mv2

gh = 1/2v2

10 x h = 1/2 x 15 x 15

20 x h = 225

h = 225/20

h = 11.25m

3 0

4 years ago

A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.

Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is $\mu _{k} =$ 0.12</h3>

Explanation:

Given :

Initial speed $v_{o} = 9.5 \frac{m}{s}$

Displacement $x = 37.4$ m

From the kinematics equation,

$v^{2} - v^{2} _{o} = 2ax$

Where $v^{2} =$ final velocity, in our example it is zero ( $v =0$ ), $a =$ acceleration.

$a =- \frac{90.25}{ 2 \times 37.4}$

$a =- 1.21 \frac{m}{s^{2} }$

From the formula of friction,

$F =- \mu _{k } N$

Minus sign represent friction is oppose the motion

Where $N = mg$ ( normal reaction force )

$ma = -\mu _{k} m g$ ( ∵ $g = 9.8 \frac{m}{s^{2} }$ )

So coefficient of friction,

$\mu_{k} = \frac{1.21}{9.8}$

$\mu_{k} = 0.12$

Therefore, the coefficient of kinetic friction between the puck and the ice is $\mu _{k} =$ 0.12 .

4 0

3 years ago

An adiabatic closed system is accelerated from 0 m/s to 34 m/s. Determine the specific energy change of this system, in kJ/kg.

prohojiy [21]

Answer:

Δe=0.578 kJ/kg

Explanation:

Given data

Velocity v₁=0 m/s

Velocity v₂=34 m/s

to find

Specific energy change Δe

Solution

The specific energy change is simply determined from change in velocity

Δe=(v₂²-v₁²)/2

Put the given values to find the specific energy change

$=(\frac{(34)^{2} *10^{-3} }{2} )\\=0.578kJ/kg$

Δe=0.578 kJ/kg

6 0

3 years ago

Read 2 more answers

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do no

Alika [10]

Answer:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

Explanation:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

$\boxed{lol}$

7 0

3 years ago