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mojhsa [17]
4 years ago
11

What would be the total voltage for the following battery configurations.

Physics
1 answer:
ohaa [14]4 years ago
4 0

Explanation:

If we're talking about li-ion batteries with a capacity of 3.6V, then the total voltages for each configuration would be:

1) 10.8V (3.6x4) Connected in series.

2) 7.2V (3.6x2) The opposing battery's voltage doesn't add.

3 ) 3.V Connected in parallel.

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When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele
algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be 2.238\times 10^{-19}j

Explanation:

In first case wavelength of electromagnetic radiation \lambda =480nm=480\times 10^{-9}m

Plank's constant h=6.6\times 10^{-34}J-s

Maximum kinetic energy = 0.54 eV

Energy is given by E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J

We know that energy is given

E=K_{MAX}+\Phi, here \Phi is work function

So 4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi

\Phi =3.585\times 10^{-19}J

Now wavelength of second radiation = 340 nm

So energy E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J

So K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j

6 0
4 years ago
A roller coaster needs to climb a tall hill. How tall of a hill can it climb with an initial
iren [92.7K]

Answer:

h = 11.25m

Explanation:

mgh = 1/2mv2

gh = 1/2v2

10 x h = 1/2 x 15 x 15

20 x h = 225

h = 225/20

h = 11.25m

3 0
4 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
An adiabatic closed system is accelerated from 0 m/s to 34 m/s. Determine the specific energy change of this system, in kJ/kg.
prohojiy [21]

Answer:

Δe=0.578 kJ/kg

Explanation:

Given data

Velocity v₁=0 m/s

Velocity v₂=34 m/s

to find

Specific energy change Δe

Solution

The specific energy change is simply determined from change in velocity

Δe=(v₂²-v₁²)/2

Put the given values to find the specific energy change

=(\frac{(34)^{2} *10^{-3} }{2} )\\=0.578kJ/kg

Δe=0.578 kJ/kg

6 0
3 years ago
Read 2 more answers
Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do no
Alika [10]

Answer:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

Explanation:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

\boxed{lol}

7 0
3 years ago
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