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3 years ago

What are the like terms in the expression? 4m-9+3n+2

Physics

2 answers:

mash [69]3 years ago

8 0

The like terms in this expression are, -9 and 2, but that is it

wel3 years ago

5 0

-9 and +2
Hope I helped :)

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Two separate but nearby coils are mounted along the same axis. A power supply controls the flow of current in the first coil, an

Setler [38]

The ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

<h3>Induced emf</h3>

An emf is induced in a coil placed in a magnetic field when a current carrying conductor moves in the field.

emf = NdФ/dt

where;

dФ is change in flux of the field
N is number of turns
dt is change in time

Thus, the ammeter will indicate that a current is flowing in the second coil only when current changes in the first coil.

Learn more about induced emf here: brainly.com/question/13744192

#SPJ1

3 0

2 years ago

A chunk of metal has a volume of

Alla [95]

Answer:

7213.7kg/m³

Explanation:

Given parameters:

Volume of the metal chunk = 0.131m³

Mass of the metal chunk = 945kg

Unknown:

Density of the metal chunk = ?

Solution :

To solve this problem, density is the mass per unit volume. It is mathematically expressed as;

Density = $\frac{mass}{volume}$

So;

Density = $\frac{945}{0.131}$ = 7213.7kg/m³

5 0

3 years ago

Why evaporation are called surface phenomenon?

Eva8 [605]

The water formed on the surface of the water evaporation loss (evaporation), consisting of plant transpiration water loss (transpiration) is called. Soil near the plant and the resulting water loss is called by evapotranspiration.

6 0

4 years ago

Read 2 more answers

Physics question 28 plz help me

Alexus [3.1K]

Answer:

a. I = 30 A

b. E = 1080000 J = 1080 KJ

c. ΔT = 12.86°C

d. Cost = $ 4.32

Explanation:

The current in the coil is given by Ohm's Law:

$V = IR\\I = \frac{V}{R}$

where,

I = current = ?

V = Voltage = 120 V

R = Resistance = 4 Ω

Therefore,

$I = \frac{120\ V}{4 \Omega}\\$

I = 30 A

The energy can be calculated as:

$E = VIt\\E = (120\ V)(30\ A)(5\ min)(\frac{60\ s}{1\ min})\\$

E = 1080000 J = 1080 KJ

For the increase in the temperature of water:

$E = mC\Delta T\\$

where,

m = mass of water = 20 kg

C = specific heat of water = 4.2 KJ/kg.°C

Therefore,

$1080\ KJ = (20\ kg)(4.2\ KJ/kg.^oC)\Delta T$

ΔT = 12.86°C

First, we will calculate the total energy consumed:

$E=(Power)(Time)\\E=VI(Time)\\E = (120\ V)(30\ A)(0.5\ h/d)(30\ d)\\E = 54000\ Wh\\E = 54 KWh$

Now, for the cost:

$Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(54\ KWh)$

Cost = $ 4.32

7 0

3 years ago

213.49 in standard form is

Rudiy27

Answer:

21349/ 100

Explanation:

7 0

3 years ago