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Anna11 [10]
3 years ago
6

What are the like terms in the expression? 4m-9+3n+2

Physics
2 answers:
mash [69]3 years ago
8 0
The like terms in this expression are, -9 and 2, but that is it
wel3 years ago
5 0
-9 and +2
Hope I helped :)

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A player bounces a basketball on the floor, compressing it to 80.0 % of its original volume. The air (assume it is essentially N
son4ous [18]

Answer: 292.95 J

Explanation:

change in internal energy= Heat transfer - work done

ΔU =Q -PΔV

Here, Q = 0 as there is no heat transfer.

P =2.00 atm = 2.00 × 101235 Pa = 202470 Pa

ΔV = final volume - initial volume = 0.8 V -V = -0.2 V

where V is the initial volume.

Volume of a spherical ball, V = \frac{4}{3}\pi r^3

r = d/2 = 23.9 cm / 2 = 0.12 m

V = \frac{4}{3}\times 3.14 \times (0.12m)^3= 7.23\times10^{-3}m^3

\DeltaU = -P\DeltaV = - 202470 Pa \times -0.2 \times 7.23\times10^{-3}m^3=292.95 J

Hence, internal energy would change by 292.95 J.

3 0
3 years ago
Read 2 more answers
Help what is the answer
Ainat [17]

Answer:

C

Explanation:

F=k\dfrac{Q_1Q_2}{r^2}= \\\\(8.99 \times 10^9)\dfrac{(-2\times 10^{-4})(8\times 10^{-4})}{0.3^2}\approx 1.6\times 10^4 N

Hope this helps!

5 0
3 years ago
1) How is density different than mass?
elixir [45]
Mass is a measure of how much matter there is within an object, typically given in grams. Mass is not affected by gravity, so a given object would have the same mass on earth as in outer space. Density is the amount of mass in an object per a certain amount of volume
3 0
3 years ago
Does coefficient of thermal expansion vary with temperature?
N76 [4]

Answer:

yes

Explanation:

8 0
3 years ago
Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compr
AnnZ [28]

Answer:

20 N/m

Explanation:

From the question,

The ball-point pen obays hook's law.

From hook's law,

F = ke............................ Equation 1

Where F = Force, k = spring constant, e = compression.

Make k the subject of the equation

k = F/e........................ Equation 2

Given: F = 0.1 N, e = 0.005 m.

Substitute these values into equation 2

k = 0.1/0.005

k = 20 N/m.

Hence the spring constant of the tiny spring is 20 N/m

8 0
3 years ago
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