Answer:
241.7 s
Explanation:
We are given that
Charge of particle=
Kinetic energy of particle=
Initial time=
Final potential difference=
We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.
We know that

Using the formula


Initial voltage=

Using the formula





Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.
Answer:
3.626 m/s
Explanation:
v=d/t
1. -0.02/0 = 0 m/s
2. 0.86/0.2 = 4.3 m/s
3. 1.71/0.4 = 4.275 m/s
4. 2.54/0.6 = 4.23 m/s
5. 3.32/0.8 = 4.15 m/s
6. 4.08/1.0 = 4.08 m/s
7. 4.79/1.2 = 3.99 m/s
8. 5.48/1.4 = 3.91 m/s
9. 6.15/1.6 = 3.84 m/s
10. 6.76/1.8 = 3.76 m/s
11. 7.37/2.0 = 3.66 m/s
12. 7.92/2.2 = 3.6 m/s
13. 8.45/2.4 = 3.52 m/s
14. 8.96/2.6 = 3.45 m/s
the mean of these numbers is 3.626
his average velocity ks 3.626 m/s
Answer:
d = 76.5 m
Explanation:
To find the distance at which the boats will be detected as two objects, we need to use the following equation:

<u>Where:</u>
θ: is the angle of resolution of a circular aperture
λ: is the wavelength
D: is the diameter of the antenna = 2.10 m
d: is the separation of the two boats = ?
L: is the distance of the two boats from the ship = 7.00 km = 7000 m
To find λ we can use the following equation:
<u>Where:</u>
c: is the speed of light = 3.00x10⁸ m/s
f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz
Hence, the distance is:

Therefore, the boats could be at 76.5 m close together to be detected as two objects.
I hope it helps you!
Answer:
hyoid bone
Explanation:
Woodpeckers have a special bone that acts like a seat-belt for its skull. It's called the hyoid bone, and it wraps all the way around a woodpecker's skull. Every time the bird pecks, the hyoid acts like a seat-belt for the bird's skull and the delicate brain it protects.