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Goryan [66]
3 years ago
9

A ball is dropped from somewhere above a window that is 2.00 m in height. As it falls, it is visible to a person boxing through

the window for 200 ms as it passes by the 2.00 m height of the window. From what height above the top of the window was the ball dropped?
Physics
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

4.14 m

Explanation:

In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .

Let in this last leg , u be the initial velocity.

s = ut + 1/2 g t²

2 = .2 u + .5 x 9.8 x .04

u = 9.02 m /s .

Let v be the final velocity in this leg

v² = u² + 2 g s

v² = (9.02)² + 2 x 9.8 x 2

= 81.36 +39.2

v = 10.97 m / s

Now consider the whole height from where the ball dropped . Let it be h.

Initial velocity u = 0

v² = u² +2gh

(10.97 )² = 2 x 9.8 h

h = 6.14 m

Height from window

= 6.14 - 2m

= 4.14 m

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Complete Question

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The ascending order would be 2nd < 1st < 3rd

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