Answer:
8.24
Explanation:
the answer is explained above
Answer:
Explanation:
Given data:
Mass of water used = 4.05 g
Mass of each product produced = ?
Solution:
Chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 4.05 g/ 18 g/mol
Number of moles = 0.225 mol
Now we will compare the moles of water with hydrogen and oxygen.
H₂O : H₂
2 : 2
0.225 : 0.225
H₂O : O₂
2 : 1
0.225 : 1/2×0.225 = 0.113 mol
Mass of hydrogen:
Mass = number of moles × molar mass
Mass = 0.225 × 2 g/mol
Mass = 0.45 g
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.113 mol × 32 g/mol
Mass = 3.616 g
1) All the CO2 comes from the C24 H30 N3 O
2) To balance C from CO2 with C from C24, the ratio of cC24 H30 N3 O to CO2 is 24 / 1
3) Convert 1.20 g of CO2 to number of moles
number of moles = mass in grams / molar mass
mass = 1.20 g
molar mass = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
number of moles = 1.2 g / 44.01 g/mol = 0.0273 mol
4) proportion
1 mol C24 H30 N3 O / 24 mol CO2 = x / 0.0273 mol CO2
=> x = 0.0273 mol CO2 * 1 mol C24H30N3O / 24 mol CO2 = 0.00114 mol C24H30N3O
5) Convert 0.00114 mol C24H30N3O to grams
molar mass = 376.5 g/mol
mass = 0.00114 mol * 376.5 g/mol = 0.429 g
6) mass percent in the mixture
mass percent = (mass of lsd / mass of mixture) * 100 = (0.429g / 1.0g) * 100 = 42.9%
Answer: 42.9%
