Answer:
I think the correct answer for this is False.
They are the tides and conditions of the oceans
Reaction of Cu(NO₃)₂ with each salt is as follow,
1) with KNO₃;
Cu(NO₃)₂ + KNO₃ → Cu(NO₃)₂ + KNO₃
Both salt products are water soluble.
2) With CuSO₄;
Cu(NO₃)₂ + CuSO₄ → CuSO₄ + Cu(NO₃)₂
Again both Salt products are water soluble.
3) With K₂SO₄;
Cu(NO₃)₂ + K₂SO₄ → CuSO₄ + 2 KNO₃
Again both salt products are water soluble.
4) With K₂S;
Cu(NO₃)₂ + K₂S → CuS + 2 KNO₃
In this case CuS is water insoluble, hence precipitates out.
Result:
Option-4 is the correct answer.
Explanation:
It is known that for a body centered cubic unit cell there are 2 atoms per unit cell.
This means that volume occupied by 2 atoms is equal to volume of the unit cell.
So, according to the volume density
![5 \times 10^{26} atoms = 1 [tex]m^{3}](https://tex.z-dn.net/?f=5%20%5Ctimes%2010%5E%7B26%7D%20atoms%20%3D%201%20%5Btex%5Dm%5E%7B3%7D)
2 atoms = 
= 
Formula for volume of a cube is
. Therefore,
Volume of the cube = 
As lattice constant (a) = 
= 
Therefore, the value of lattice constant is
.
And, for bcc unit cell the value of radius is as follows.
r = 
Hence, effective radius of the atom is calculated as follows.
r = 
= 
= 
Hence, the value of effective radius of the atom is
.