1297 grams of ore are needed to obtain 454.0 grams of Fe.
As the iron ore sample if found to be 35 percentage by mass
It means 35g of iron is present in 100g of ore.
1g of iron is present in 100/35 g of ore
And 454.0 g of iron is present in 100 × 454 / 35
= 1297.14 or 1297 grams (approx.)
The mass percent is calculated by dividing the mass of the compound or solute by the mass of the element or solute. A percent is obtained by multiplying the result by 100.
The formula for an element's percentage in a compound is as follows:
mass percent is calculated by multiplying the mass of the element in one mole of the compound by one hundred.
A solution follows this formula:
(gm of solute / gm of solute plus solvent) × 100 equals mass percent.
or
(gm of solute/grams of solution) x 100 Equals mass percent
Hence, 1297 grams of ore are needed to obtain 454.0 grams of Fe.
Learn more about Mass percent here brainly.com/question/26150306
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i think A but if I'm wrong sorry
then if increasing then becoming spread out so letter A
When we show the structure of a molecule, we see the arrangement of atoms in the molecule.
<h3>Structure of molecules</h3>
The structure of a molecule shows the arrangement of atoms in the molecule.
1) There are 24 carbon atoms in the molecule.
2) There are 30 p- orbitals that are involved in pi bonds in the molecule.
3) We need to add 22 lone pairs of electrons
4) We do not need to add any formal positive charge to the molecule.
Learn more about molecules: brainly.com/question/19922822
Answer:
new solubility = 0.443 g/l
Explanation:
To solve this question, we will use Henry's law.
Henry's law states that, at constant temperature:
S1 / P1 = S2 / P2
We are given that:
S1 = 0.16 g/l
P1 = 104 kPa
S2 is the solubility we want to calculate
P2 = 288 kPa
Substitute with the givens in the above relation to get the new solubility (S2) as follows:
0.16 / 104 = S2 / 288
S2 = (0.16/104) * 288
S2 = 0.443 g/l
Hope this helps :)
A lot of data and making theories