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3 years ago

Solve this inequality (show your work) 30x+ 600 ≥ 1,500

Mathematics

2 answers:

12345 [234]3 years ago

8 0

Answer:

x ≥ 30

Step-by-step explanation:

30*30 = 900 and when we add 600 to that, we get 1,500 which is the lowest possible number for the left side of the equation to equal. If x equals anything above 30, then it will automatically equal a number greater than 1,500 when added to 600.

(sorry this is confusing, I'm not very good at explaining things. I hope it helped anyway)

olganol [36]3 years ago

4 0

Answer:

x > 30

Step-by-step explanation:

replace > with=

30x +600=1500

take 600 to the other side

30x=1500-600

30x=900

x=30

therefore x > 30

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Step-by-step explanation:

Step 1: Put your numbers in ascending order (from smallest to largest). For this particular data set, the order is

14, 18, 28, 29, 32, 44, 48, 50, 65

Step 2: Find the minimum and maximum for your data set. Now that your numbers are in order, this should be easy to spot.

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Maximum = 65

Step 3: Find the median. The median is the middle number. The middle number in your list is 32, so

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Step 4: Place parentheses around the numbers above and below the median.

(14, 18, 28, 29), 32, (44, 48, 50, 65)

Step 5: Find Q1 and Q3. Q1 can be thought of as a median in the lower half of the data, and Q3 can be thought of as a median for the upper half of data.

First quartile

$\bf{Q_1=\dfrac{18+28}{2}=\dfrac{46}{2}=23}$

Third quartile

$\bf{Q_3=\dfrac{48+50}{2}=\dfrac{98}{2}=49}$

Step 6: Write down your summary found in the above steps.

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Median = 32

$Q_3=49$

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