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CaHeK987 [17]
3 years ago
13

Hi i need the answer to this

Mathematics
1 answer:
inna [77]3 years ago
7 0

Answer:

She forgot about the negative sign in front of the 3.7, therefore, she added 3.7 to -3.3 which is equals to 0.4

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Which of the following is equivalent to 7a^4+3a^4
nasty-shy [4]
Give me a list for me to answer

2,401a+81a
is equivalent
3 0
3 years ago
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The perimeter of a triangle is 34cm. What are the lengths of the sides if the first side is twice the length of the second side
dybincka [34]

Answer:

8sm, 16sm, 10sm

Step-by-step explanation:

the first side of the triangle: x

the other side of the triangle: 2x

the third side of the triangle: x+2

the perimeter of the triangle: x+2x+x+2=34

4x=32

x=8

2*8=16

8+2=10

4 0
2 years ago
Question 6
inn [45]

Answer:

c

Step-by-step explanation:

4 times 2 is 8. 3 and 3 times -4 is -12

8 minus -12 is negative 4

7 0
3 years ago
Divide 29 into two parts so that the sun of the squares of the parts is 425.Find the value of each Part.
Taya2010 [7]

Answer:

13 and 16

Step-by-step explanation:

let the 2 parts be x and y, then

x + y = 29 → (1) and

x² + y² = 425 → (2)

From (1) → x = 29 - y → (3)

substitute x = 29 - y into (2)

(29 - y)² + y² = 425 ( expand factor )

841 - 58y + y² + y² = 425 ( rearrange into standard form )

2y² - 58y + 416 = 0 ← in standard quadratic form

divide all terms by 2

y² - 29y + 208 = 0

Consider the factors of 208 which sum to - 29

These are - 13 and - 16, hence

(y - 13)(y - 16) = 0

equate each factor to zero and solve for y

y - 13 = 0 ⇒ y = 13

y - 16 = 0 ⇒ y = 16

substitute these values into (3)

x = 29 - 13 = 16 and x = 29 - 16 = 13

The 2 parts are 13 and 16


4 0
3 years ago
Read 2 more answers
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
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