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Lady bird [3.3K]
3 years ago
15

Bank service charges are automatically deducted from the bank account, why are these recorded in the cash payments journal

Mathematics
1 answer:
hram777 [196]3 years ago
8 0

Answer:

False

Step-by-step explanation:

You might be interested in
Using linked lists or a resizing array; develop a weighted quick-union implementation that removes the restriction on needing th
balu736 [363]

Answer:

Step-by-step explanation:

package net.qiguang.algorithms.C1_Fundamentals.S5_CaseStudyUnionFind;

import java.util.Random;

/**

* 1.5.20 Dynamic growth.

* Using linked lists or a resizing array, develop a weighted quick-union implementation that

* removes the restriction on needing the number of objects ahead of time. Add a method newSite()

* to the API, which returns an int identifier

*/

public class Exercise_1_5_20 {

public static class WeightedQuickUnionUF {

private int[] parent; // parent[i] = parent of i

private int[] size; // size[i] = number of sites in subtree rooted at i

private int count; // number of components

int N; // number of items

public WeightedQuickUnionUF() {

N = 0;

count = 0;

parent = new int[4];

size = new int[4];

}

private void resize(int n) {

int[] parentCopy = new int[n];

int[] sizeCopy = new int[n];

for (int i = 0; i < count; i++) {

parentCopy[i] = parent[i];

sizeCopy[i] = size[i];

}

parent = parentCopy;

size = sizeCopy;

}

public int newSite() {

N++;

if (N == parent.length) resize(N * 2);

parent[N - 1] = N - 1;

size[N - 1] = 1;

return N - 1;

}

public int count() {

return count;

}

public int find(int p) {

// Now with path compression

validate(p);

int root = p;

while (root != parent[root]) {

root = parent[root];

}

while (p != root) {

int next = parent[p];

parent[p] = root;

p = next;

}

return p;

}

// validate that p is a valid index

private void validate(int p) {

if (p < 0 || p >= N) {

throw new IndexOutOfBoundsException("index " + p + " is not between 0 and " + (N - 1));

}

}

public boolean connected(int p, int q) {

return find(p) == find(q);

}

public void union(int p, int q) {

int rootP = find(p);

int rootQ = find(q);

if (rootP == rootQ) {

return;

}

// make smaller root point to larger one

if (size[rootP] < size[rootQ]) {

parent[rootP] = rootQ;

size[rootQ] += size[rootP];

} else {

parent[rootQ] = rootP;

size[rootP] += size[rootQ];

}

count--;

}

}

public static void main(String[] args) {

WeightedQuickUnionUF uf = new WeightedQuickUnionUF();

Random r = new Random();

for (int i = 0; i < 20; i++) {

System.out.printf("\n%2d", uf.newSite());

int p = r.nextInt(i+1);

int q = r.nextInt(i+1);

if (uf.connected(p, q)) continue;

uf.union(p, q);

System.out.printf("%5d-%d", p, q);

uf.union(r.nextInt(i+1), r.nextInt(i+1));

}

}

}

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
gladu [14]

Answer:

Part 1) 2x^{2}-32=0----> (-4,4)

Part 2) 4x^{2}-100=0----> (-5,5)

Part 3) x^{2}-55=9----> (-8,8)

Part 4) x^{2}-140=-19----> (-11,11)

Part 5) 2x^{2}-18=0----> (-3,3)

see the attached figure

Step-by-step explanation:

Solve each quadratic equation

Part 1) we have

2x^{2}-32=0

Adds 32 both sides

2x^{2}=32

Divide by 2 both sides

x^{2}=16

take square root both sides

x=\pm4

therefore

The solutions are (-4,4)

Part 2) we have

4x^{2}-100=0

Adds 100 both sides

4x^{2}=100

Divide by 4 both sides

x^{2}=25

take square root both sides

x=\pm5

therefore

The solutions are (-5,5)

Part 3) we have

x^{2}-55=9

Adds 55 both sides

x^{2}=9+55

x^{2}=64

take square root both sides

x=\pm8

therefore

The solutions are (-8,8)

Part 4) we have

x^{2}-140=-19

Adds 140 both sides

x^{2}=-19+140  

x^{2}=121

take square root both sides

x=\pm11

therefore

The solutions are (-11,11)  

Part 5) we have

2x^{2}-18=0

Adds 18 both sides

2x^{2}=18

Divide by 2 both sides

x^{2}=9

take square root both sides

x=\pm3

therefore

The solutions are (-3,3)

7 0
3 years ago
Write an equation to find the total number of the hours h the instructor exercises in any number of weeks w.
8090 [49]

Answer:

wh/w=h

Step-by-step explanation:

in a day the no.  of hours are h and ythe no of weeks are w

so wh/w=h

3 0
3 years ago
Write -41.27 as a mixed number.
Salsk061 [2.6K]

Answer:

-41 27/100

Step-by-step explanation:

4 0
2 years ago
PLEASE ANSWER BOTH QUESTIONS. Use Graph to help answer them. NO LINKS.
koban [17]

Answer:

a - 12 seconds (1/5 minute)

b - 5

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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