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3 years ago

A stove costs $695 will be on sale next week for 20% off its regular price. What is the amount of savings

Mathematics

1 answer:

jonny [76]3 years ago

3 0

Answer:

It would be 139$

Step-by-step explanation:

In order to find a percent of a value you first move the decimal place over 2 to the left or divide by 100(percentage is no longer there). In this case it would be .20. You multiply that with the total number(695) and the product is your answer.

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The sum of two numbers is -17. Their difference is 41. Find the numbers

Alex787 [66]

Answer:

x = 12

y = -29

Step-by-step explanation:

Our given equations: x + y = -17 and x - y = 41

Solve for x and substitute.

x = -17 - y

(-17 - y) - y = 41

-17 - 2y = 41

2y = -58

y = -29

Solve for x using y

x + (-29) = -17

x = 12

3 0

2 years ago

What is 9 + 10? This is hard homework

Lubov Fominskaja [6]

9 + 10=21 :)
9=3 x3
10= 2 x 5
3x5=15
3x2=6
15 + 6 = 21 :)

4 0

3 years ago

A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we select appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

μ = $970

σ = $129

n = 102

Since the sample size is quite large, i.e. n = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

$P (\sum X \leq 100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}$

$=P(Z$

*Use a z-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0

2 years ago

Car mart pays $110,000 rent each year for its two-story building. the space in this building is occupied by five departments as

Anvisha [2.4K]

First floor:

paint department 1,575 square feet

space engine department 2,925 square feet

Total = 4,500 square feet

Second floor:

space window department 1,845 square feet

electrical department 765 square feet

accessory department 1,890 square feet

Total = 4,500 square feet

Since 70% is allocated to the 1st floor, therefore the floor is receiving:

First floor expense = $110,000 * 0.70 = $77,000

Second floor expense = $110,000 - $77,000 = $33,000

The expense for each department is the proportion on the total expense per floor.

First floor:

paint department = (1575/4500) * 77,000 = $26,950

space engine department = 77,000 – 26,950 = $50,050

Second floor:

space window department = (1845/4500) * 33,000 = $13,530

electrical department = (765/4500) * 33,000 = $5,610

accessory department = 33,000 – 13530 – 5610 = $13,860

6 0

3 years ago

Help help math math math

Anarel [89]

Answer:

i think this is right i hope it helped :)

Step-by-step explanation:

5m - 8 = 2m + 1

5m + 2m - 8 = 1

7m - 8 = 1

7m = 7

m = 1

6 0

2 years ago

Read 2 more answers