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Effectus [21]
3 years ago
14

(3x+20)=(5x-16) Find the value of X

Mathematics
2 answers:
Rudiy273 years ago
5 0

Step-by-step explanation:

(3x+20)=(5x-16)

combination of like terms

3x-5x= -16-20

-2x= -36

x= -36/-2

x=18

lubasha [3.4K]3 years ago
3 0

Answer:

x = 18

Step-by-step explanation:

3x + 20 = 5x - 16

Subtract 20 from both sides

3x + 20 - 20 = 5x - 16 -20

3x = 5x -36   {Now subtract 5x from both sides}

3x - 5x = 5x - 36 +5x

-2x = -36    {Divide both sides by (-2)}

-2x/-2 = -36/-2

x = 18

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An ant looks up to the top of a building at an angle of elevation of 32°. Then, the ant walks an additional 88 feet from the edg
Naddik [55]
Tanα=h/x, tanß=h/(x+88)

solving both for x

x=h/tanα, x=h/tanß-88, since x=x

h/tanα=h/tanß-88

h/tanß-h/tanα=88

(htanα-htanß)/(tanα*tanß)=88

h(tanα-tanß)/(tanα*tanß)=88

h=88(tanα*tanß)/(tanα-tanß)

Since α=32 and ß=22...

h=88(tan32*tan22)/(tan32-tan22)

h≈85.3 feet


8 0
3 years ago
Explain how to find the area of the triangle when x = 3 inches. then find the area
geniusboy [140]

To find the area of a triangle, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into 2 triangles.

3 0
3 years ago
Read 2 more answers
Benjamin’s and David’s ages add up to 36 years. The sum of twice their respective ages also add up to 72 years. Find their ages
nydimaria [60]
Answer:Benjamin’s age = 30 and David’s age = 6

Explanation:

Let x be the age of Benjamin
Let y be the age of David

x + y = 36

And 2x + 2y = 72

If we plug 30 for x and 6 for y we get:

30 + 6 = 36
36 = 36

2(30) + 2(6) = 72
60 + 12 = 72
72 = 72

=

5 0
3 years ago
Read 2 more answers
A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11
mixer [17]
Let A(t) denote the amount of salt in the tank at time t. We're given that the tank initially holds A(0)=100 lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}
\implies A'(t)+\dfrac{11}{200+33t}A(t)=484

Find the integrating factor:

\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}

Distribute \mu(t) along both sides of the ODE:

(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}
\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}
A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt
A(t)=22(200+33t)^{2/3}+C

Since A(0)=100, we get

100=22(200)^{2/3}+C\implies C\approx-652.39

so that the particular solution for A(t) is

A(t)=22(200+33t)^{2/3}-652.39

The tank becomes full when the volume of solution in the tank at time t is the same as the total volume of the tank:

200+(44-11)t=500\implies 33t=300\implies t\approx9.09

at which point the amount of salt in the solution would be

A(9.09)\approx733.47\text{ lb}
4 0
3 years ago
Answer this fast and I’ll make you Brainly
Murrr4er [49]

Answer:

7

Step-by-step explanation:

Please find the solution in the image attached below.

Hope this helps!

5 0
3 years ago
Read 2 more answers
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