A is located at (1,3) D is located at (5,0)
distance formula is sqrt((x2-x1)^2 +(y2-y1)^2)
= sqrt(( 5-1)^2 + (0-3)^2)
= sqrt((4^2 +-3^2)
= sqrt (16+9)
= sqrt(25)
= 5
distance is 5 units
The answer to your question is 2 5/27
First, I would reduce 3/15 and 15/21 to simplest form.
1/5, 5,7
You could list multiples of all your denominators. But in this case, because two of your denominators are already prime (5 and 7), you can just multiply the three denominators together.
5 x 7 x 8
This will give you the LCD
The answer is 2c - 72.
First complete the brackets.
46+26=72
Then subtract 4c from 2c.
4c-2c=2c