1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garri49 [273]
3 years ago
13

Please help!! Can you please tell me how to do this!!!

Mathematics
1 answer:
Alborosie3 years ago
4 0
9. increase
10. decrease
11. increase
12. decrease
13. decrease
14. decrease
15. increase
16. increase
You might be interested in
1. m- 7 5.5
Andreas93 [3]
The first answer is 2.5 and I don’t know the last two sorry
5 0
3 years ago
What is Melissa’s original salary if she gets 4% increase in pay and is now getting $29,12? Round to the nearest dollar.
andre [41]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Help :( math for 8th
rewona [7]

Answer:

She should add 10x to both sides

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Elapsed time 2 hr 37 min, end time: 1:15. start time?
3241004551 [841]

Answer:

10:38

Step-by-step explanation:

2 hours back from 1:15

11:15

37 minutes back from 11:15

10:38

The start time is 10:38.

6 0
3 years ago
Read 2 more answers
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
Other questions:
  • Simplify the expression 1/√(1-cos^2 x) . Remember cos x= 1/csc x
    5·1 answer
  • A building contractor has a piece of crown molding that is 48 1/2 in. Long. He cuts off one piece measuring 10 1/4 in. and anoth
    10·2 answers
  • Fill in the blank.<br> 65+26 is the same as 61 +
    15·2 answers
  • True or false: the line drawn within the box of the boxplot always represents the arithmetic mean.
    13·1 answer
  • Please i need help !!!!!!!!!!!!!!!!!
    12·2 answers
  • Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = 5y cos(z) i + ex sin(z) j + xey k, S is the hemisphere x2 + y2 + z2
    5·1 answer
  • PLEASE HELP!!!!! very urgent asap!!! need help please
    12·2 answers
  • Help my homework pls!!!!!!​
    15·1 answer
  • What is the image of (-6, -2) after a dilation by a scale factor of 4 centered at the origin?​
    10·1 answer
  • Given the function defined in the table below, find the average rate of change, in
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!