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2 years ago

What is the product? 4 • (–5)

Mathematics

2 answers:

AysviL [449]2 years ago

6 0

Answer:

4×(-5)=-20

Step-by-step explanation:

Pavlova-9 [17]2 years ago

6 0

Answer:

$\huge \boxed{-20}$

Step-by-step explanation:

$4*(-5)$

$\Rightarrow 4* -5$

Multiplying.

$\Rightarrow -20$

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Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes __and___

serious [3.7K]

Answer:

The x-intercepts of the quadratic function are -7 and 5.

Step-by-step explanation:

The given function is

$f(x)=x^2+2x-35$

Equate f(x)=0, to find the x-intercepts of the function.

$x^2+2x-35=0$

$x^2+7x-5x-35=0$

$x(x+7)-5(x+7)=0$

$(x+7)(x-5)=0$

$x+7=0\Rightarrow x=-7$

$x-5=0\Rightarrow x=5$

Therefore the x-intercepts of the quadratic function are -7 and 5.

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2 years ago

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Jeff finds some bugs. he finds 10 fewer grasshopper than ladybugs. if jeff finds 5 grasshoppers how many lady bugs does jeff fin

NemiM [27]

There's not enough information to figure out the grasshoppers, but there should be 15 lady bugs, because 5+10=15

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Celeste wants to have a haircut and permed and also go to lunch. she knows she will need $77. the perm will cost twice as much a

Elza [17]

$48 is the cost of the perm

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2 years ago

56: =24:3

dmitriy555 [2]

56:7=24:3
3x3=27:3
8x2=64:4
45:9=35:7
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2 years ago

Could the inverse of a non-function be a function? Explain or give an example.

Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form $(a,\, b)$ . The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.

A mapping is a function if and only if for each possible input value $x$ , at most one of the distinct pairs includes $x\!$ as the value of first entry.

For example, the mapping $\lbrace (0,\, 0),\, (1,\, 0) \rbrace$ is a function. However, the mapping $\lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace$ isn't a function since more than one of the distinct pairs in this mapping include $1$ as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping $\lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace$ is the mapping $\lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace$ .

Consider mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ . This mapping isn't a function since the input value $0$ is the first entry of more than one of the pairs.

Invert $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ as follows:

$(0,\, 0)$ becomes $(0,\, 0)$ .
$(0,\, 1)$ becomes $(1,\, 0)$ .
$(1,\, 0)$ becomes $(0,\, 1)$ .
$(1,\, 1)$ becomes $(1,\, 1)$ .

In other words, the inverse of the mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ would be $\lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!$ , which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function $\mathbb{R} \to \mathbb{R}$ mappings, including circles) are also non-function mappings.

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2 years ago