(2x+3y)+(8x+10y) simplify the following
2 answers:
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Answer:
34cm²
Step-by-step explanation:
Find diagram in the attached file.
Since each square on the grid represent 1cm², the length of the each square will be 1cm
Area of the irregular shape can be gotten by breaking the irregular shape into three shapes which are the triangle, rectangle and a parallelogram.
Area of the irregular shape = area of triangle + area of rectangle + area of parallelogram
For TRIANGLE
Area of triangle = 1/2×base×height
Since the base of triangle is on 4square grid,
Base = 4cm
Height = 2cm
Area = 1/2×4×2
Area of ∆ = 4cm²
FOR RECTANGLE
Area of rectangle = Length ×Breadth
Length = 3cm
Breadth = 5cm
Area of the rectangular shape = 3×5
= 15cm²
FOR PARALLELOGRAM
Area of a parallelogram = Base × Height
Base = 5cm
Height = 3cm
Area = 5cm×3cm
Area = 15cm²
Area of the irregular shape = 4cm²+15cm²+15cm²
=34cm²
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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