I think your answer is D. However I’m not 100% sure.
Your solution steps look correct, but the answer was not completed. Given that QR = 33.8 and PQ = 57.6, and Q is the right angle, then tan P = opposite / adjacent = QR / PQ = 33.8 / 57.6 = 0.586.
Then tan P = 0.586
Angle P = tan^-1 (0.586) = 30.4 degrees.
_2k + _F2—> _2KF
put a 2 before the K and before the KF and you’re all good. it needed to be balanced with the F2
Explanation:
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.
But when we move from top to bottom in a group then there occurs an increase in size of the atoms. Hence, ionization energy decreases along a group.
(a) As Sb, Sn and I are all period 5 elements. Hence, these elements are arranged in order of increasing 
as follows.
Sn < Sb < I
(b) As Sr, Ca, and Ba are all elements of group 2a. Hence, these elements are arranged in order of increasing as follows.
Ba < Sr < Ca
Ocean currents move both warm and cool water across many miles. Warm water can be carried to a cooler place like Alaska. It can bring warmer temperatures as well as warmer water to Alaska. Just like the warm water, cold water can do this as well. If cold water moves from Alaska to The Gulf of Mexico, it can cause the water and air to cool. As air travels over the ocean water vapor can condense into it. The current’s flow depends on what variables are in play. There are many different currents that connect together to heat up and cool off as they move.
