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stepladder [879]
3 years ago
8

Tin was among the first metals used by humans. Elemental tin is produced by heating tin(IV) oxide, the principal ore of tin, wit

h carbon. The products of this reaction are tin and carbon dioxide. When the equation is written and balanced, what is the coefficient of carbon?a. 1b. 2c. 3d. 4
Chemistry
1 answer:
insens350 [35]3 years ago
4 0

<u>Answer:</u> The coefficient of carbon in the chemical reaction is 1.

<u>Explanation:</u>

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

The chemical equation for the reaction of tin (IV) oxide and carbon follows:

SnO_2+C\rightarrow Sn+CO_2

By Stoichiometry of the reaction:

1 mole of tin (IV) oxide reacts with carbon to produce 1 mole of elemental tin and carbon dioxide.

Hence, the coefficient of carbon in the chemical reaction is 1.

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Answer:

2.7 × 10⁻⁴ bar

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Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

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Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1
anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

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