How would you solve the following geometry problem?: ∆PQR, find the measure of ∡P. In Triangle PQR where angle Q is a right angl
e. QR measures 33 point 8; PQ measures 57 point 6; measure of angle P is unknown. Answers: 30.4° 35.9° 54.1° 59.6° What I did: equation: tan(x) = 33.8/57.6 tan(x)=0.56 But I know that isn't correct.
Your solution steps look correct, but the answer was not completed. Given that QR = 33.8 and PQ = 57.6, and Q is the right angle, then tan P = opposite / adjacent = QR / PQ = 33.8 / 57.6 = 0.586. Then tan P = 0.586 Angle P = tan^-1 (0.586) = 30.4 degrees.
The density will remain the same no matter how many times you cut the gold. The density is g/cm³ or g/mL. Density is essentially how many grams 1 mL of a compound weighs.
