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3 years ago

Please help! Given the regular hexagon, find the measure of each numbered angle.

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

5 0

Answer:

The answer is C. m<1=60 degrees m<2=30 degrees and m<3 equals 60 degrees

Step-by-step explanation: So, if 1 was 60 degrees then half of it is 30 degrees which is the angle for two. Them 3 is the same degree as 1.

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Zinaida [17]

Given:

EFGH is a square.

To find:

The $m\angle FHG$ .

Solution:

We know that all interior angles of a square are right angles.

$m\angle EHG=90^\circ$ (Right angle)

The diagonals of square are always the angle bisectors.

FH is a diagonal of the square. So, it bisects the angle EHG.

$m\angle FHG=\dfrac{m\angle EHG}{2}$

$m\angle FHG=\dfrac{90^\circ}{2}$

$m\angle FHG=45^\circ$

Therefore, the measure of angle FHG is 45 degrees.

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2 years ago

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GarryVolchara [31]

Because Line 1 is parallel to Line 2, angle "a" should also be 46 degrees. b is complementary so it would be 180-46=134(degrees).

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Answer:

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2 years ago

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2 years ago

Read 2 more answers

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

2 years ago