<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
Answer:
Y= 0. There is two that says that so I don't know if it's A or C
1. To solve for x, you can see that nearby C and D, the two angles are equal. We can ,therefore, make an equation and solve it:
5x - 29 = 3x + 19
- 3x
2x - 29 = 19
+ 29
2x = 48
÷ 2
x = 24
2. So for this part you would substitute the value of x and then minus that angle from 180:
3 × 24 = 72
72 + 7 = 79°
180 - 79 = 101° = ∠1
3. 180 = 101 = 79° = ∠2
4. 180 - 79 = 101° = ∠3
5. Angle 4 is equal to angle 3 because there is an alternate angle (z angle) so 101° = ∠4
6. 180 - 101 = 79° = ∠5
7. 180 - 101 = 79° = ∠6
8. To find angle 7, you have to substitute in x again, so:
5 × 24 = 120
120 - 29 = 91
180 - 91 = 89° = ∠7
9. Angle 8 is the same as angle 7 because they are opposite angles, so 89° = ∠8
10. Angles 2 and 3 are supplementary, which means they add up to 180°.
I hope this helps! :)
