Y = 2×2square+ 4× - 2 value
1 answer:
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The solution set for the both equation is (3,0) and (-1,0)
We have given that the equation
We have to determine the solution to the first equation
<h3>What is the quadratic equation formula?</h3>
Now use this value we have to find the value of y
When x=3 then
y=(3)^2-2(3)-3
y=9-6-3
y=0
When x=-1 then y=1-2(-1)-3
y=1+2-3
y=0
Therefore the solution set for both equations is (3,0) and (-1,0).
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