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3 years ago

Y = 2×2square+ 4× - 2 value

Mathematics

1 answer:

Crazy boy [7]3 years ago

6 0

Answer:

y=2(2x+3)

Step-by-step explanation:

y=2*2^2+4x-2

y=8+4x-2

y=4x+6

y=2(2x+3)

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What is the answer to the top question

Dimas [21]

3.2w/8 l=x w/5 l
X= 5• 3.2/8= 16/8=2 centimeters

7 0

3 years ago

Mixed number fraction 7 1/5+3 2/5

andrezito [222]

Answer: 10 3/5

Step-by-step explanation: 7+3 = 10

1+2=3

keep donomin

8 0

3 years ago

Read 2 more answers

I need help please. I need the the discount and selling price. Thank you

salantis [7]

Answer:

<h2><u>15.12 is the discount</u></h2><h2><u>68.88 is the sell price</u></h2>

Step-by-step explanation:

When you are taking off percentages from numbers, you first want to make the percent a number. This step is super simple. Just divide the 18 by 100

This gets you 0.18

Now multiply

84 * 0.18 = 15.12

So 15.12 is the discount

Then take 84 and subtract 15.12

84 - 15.12 = 68.88

So 68.88 is the sell price

5 0

2 years ago

PLEASE HELP!!!

Marrrta [24]

Answer:

c²(1 + 3d)

Step-by-step explanation:

The sum of square of c and d is;

c² + d

Twice the product of c and d is;

2c²d

Because c² + d is increased by 2c²d the algebraic expression becomes;

c² + d + 2c²d

c²(1 + 3d)

8 0

2 years ago

An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

<em>Point a:</em>

The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

<em>Point b:</em>

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago