Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
(4.25,2)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates and divide by 2
x = (3+5.5) /2 = 8.5/2 =4.25
To find the y coordinate of the midpoint, add the y coordinates and divide by 2
y = ( 4+0)/2 = 4/2 =2
I’m not sure if I remember well but I think it’s the answer!
Answer:
19200 ft
Step-by-step explanation:
first you convert it based on 1 in = 20 ft
8*20=160
6*20=120
now you multiply to find area
remember area is a = lw
160*120=19200
add units
19200 ft
Answer:
2(1 - 6x)
Step-by-step explanation:
2-12x
Common factor: 2
Factored equation:
2(1 - 6x)
