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swat32
4 years ago
15

Determine algebraically whether the function is even, odd, or neither even nor odd.

Mathematics
1 answer:
AfilCa [17]4 years ago
5 0

Answer:

Given Function is an even function

Step-by-step explanation:

<u>Explanation</u>:-

<u>Even function</u> :-

A function f is even if the graph of f is symmetric with respective to the y - axis.

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f.

<u>Odd function</u> : -

A function f is odd if the graph of f is symmetric with respective to the origin

Algebraically, f is odd if and only if f(-x) = - f(x) for all x in the domain of f.

given function is f(x) = 3 x^2-1

f(-x) = 3 (-x)^2-1=3 x^2 -1 = f(x)

therefore f(-x) = f(x)

given function is an even function.

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tiny-mole [99]

Answer:

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Step-by-step explanation:

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Using the cosine ratio in the right triangle

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3 years ago
Suppose we want a 90% confidence interval for the average amount of time (in minutes) spent per week on homework by the students
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Answer: 482

Step-by-step explanation:

Formula to find the sample size is given by :-

n= (\dfrac{z^*\times \sigma}{E})^2                                    (1)

, where z* = critical z-value (two tailed).  

\sigma = Population standard deviation and E = Margin of error.

As per given , we have

Margin of error : E= 3

\sigma=40

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Significance level =\alpha=1-0.90=0.10

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4 years ago
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Answer:

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dy/dx=1/2-sin x

dy/dx=0,gives

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or at x=π/6,-11 π/6

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