Try this:
1. sum of numbers is x+y=67, the difference between them is x-y=11
2. it is possible to make up and resolve the system:
$\left \{ {{x+y=67} \atop {x-y=11}} \right. \ =\ \textgreater \ \ \left \{ {{x=39} \atop {y=28}} \right.$

8 0

2 years ago

Which rule can you use to find the nth term of an arithmetic sequence in which the common difference is 5 and a12 = 63?

iren2701 [21]

Tn = a + (n-1)d

when n = 12, tn = 63

63 = a + (12-1)*5

a = 63 - 55 =8

tn or an
= 8 + (n-1) 5

= 3 + 5n

Hope this helps

4 0

2 years ago

200-[(50-4)×3+5]<br><img src="https://tex.z-dn.net/?f=200%20-%20%28%2850%20-%204%29%20%5Ctimes%203%20%2B%205%29" id="TexFormula1

lbvjy [14]

200 - [ ( 50 - 4 ) × 3 + 5 ]
= 200 - [ 46 × 3 + 5 ]
<Put brackets around the 2 number that enclose the times sign as a reminder to do that first>
= 200 - [ ( 46 × 3 ) + 5 ]
= 200 - [ 138 + 5 ]
= 200 - (143)
= 57

Hope this helps!

3 0

2 years ago