Plllllllllzzzzzzzzzzzzzzzzz helpppp meeeeeeeeeeeeeeeeeee

Mathematics

1 answer:

DochEvi [55]3 years ago

5 0

Step-by-step explanation:

radius(CE)=diameter/2=9

EF=8inch

DE=8/2=4inch

pythagorean theorem:

im right triangle,

a^2+b^2=c^2

4^2+b^2=9^2

16+b^2=81

b^2=81-16

b^2=65

b=√65

√65≈8.06

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What is the excluded value of a/b-2

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The correct excluded value is 2.

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3 years ago

Who knows how to do this ughhh I need help!

suter [353]

Answer:

$\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}$

Step-by-step explanation:

$Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}$