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Aleksandr [31]
4 years ago
11

What are all the sets of numbers for 2/3

Mathematics
1 answer:
11Alexandr11 [23.1K]4 years ago
8 0
4/6, 6/9, 8/12, 10/15, 12/18, 14/21, 16/24, 18/27, etc.<span />
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Help and explain tyty:)
Kamila [148]
I hope this one help you

6 0
3 years ago
Out of 25 students, 15 students are girls. what is the ratio of boys and girls? a: 3:5 b: 2:5 c: 2:3
Vadim26 [7]

Answer:

Answer: C 2:3

Step-by-step explanation:

total students = 25

total girls = 15

total boys = 25-15 = 10

boys:girls = 10:15

divide by 5 to get 2:3

6 0
2 years ago
Say that a supplier claims they are 99% confident that their products will be in the interval of 50.02 to 50.38. You take sample
nydimaria [60]

Answer:

The supplier becomes less accurate than they otherwise would have tried to claim. A further explanation is below.

Step-by-step explanation:

According to the provider, this same width of that same confidence interval would be as follows:

= 50.38 - 50.02

= 0.36

Depending on the input observed, the width including its confidence interval would be as follows:

= 50.39 - 50.01

= 0.38

As even the width of that interval again for survey asserted > the width including its confidence interval according to the provider's statement, we could conclude that such is the appropriate reaction.

3 0
3 years ago
Kellie currently has an average of 75 in her English class. If her grade is the mean of all her assignments, what would a grade
andriy [413]

Answer:

I just summited it, it was "Her mean grade would go up".

Step-by-step explanation:

8 0
3 years ago
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
3 years ago
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