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2 years ago

Complete the solution of the equation. Find the value of y when x equals 15.

Mathematics

1 answer:

Mariulka [41]2 years ago

8 0

Answer:

y = -6 PLEASE GIVE BRAINLIEST

Step-by-step explanation:

-15 - 9y = 39

39 + 15 = 54

-9y =54

y = 54 ÷ -9 = -6

y = -6

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True or false: The base of a polyhedron is also a face of the polyhedron

Katena32 [7]

True: A face of a polyhedron is simply a flat boundary that helps forms the 3D solid.

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3 years ago

Which equation is equivalent to n + 4 = 11? *

dangina [55]

Answer:

(n + 4) *2 = 11 * 2

Step-by-step explanation:

(n + 4) *2 = 11 * 2

Divide both sides by 2

$\frac{(n + 4) *2}{2} = \frac{11 * 2}{2}$

n + 4 = 11

5 0

3 years ago

100 points gor correct answer Identify the base of a triangle in which h=(3x+15) ft and A=(15x+75) ft^2.

ivolga24 [154]

Answer:

b = 10

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = $\frac{1}{2}$ bh ( b is the base and h the height )

Here h = 3x + 15 and A = 15x + 75, thus

$\frac{1}{2}$ × b × (3x + 15) = 15x + 75

Multiply both sides by 2 to clear the fraction

b(3x + 15) = 30x + 150

Divide both sides by (3x + 15)

b = $\frac{30x+150}{3x+15}$ ← factor numerator and denominator

= $\frac{30(x + 5)}{3(x+5)}$ ← cancel the factor (x + 5) on numerator/denominator

= $\frac{30}{3}$

= 10

7 0

2 years ago

Read 2 more answers

I NEED HELP PLEASEE

xenn [34]

$\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}$

$\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill$

5 0

3 years ago

Which equation represents the polynomial function with zeros –3, 1, and 2, and a y-intercept of –12?

storchak [24]

To generate the equation we set up the factors
(x+3) * (x-1) * (x-2) which equals
x^2 + 2x -3 * (x-2)
x^3 +2x^2 -3x -2x^2 -4x +6 equals
x^3 -3x -4x +6 which equals

x^3 -7x +6

8 0

2 years ago