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telo118 [61]
2 years ago
15

Complete the solution of the equation. Find the value of y when x equals 15.

Mathematics
1 answer:
Mariulka [41]2 years ago
8 0

Answer:

y = -6   PLEASE GIVE BRAINLIEST

Step-by-step explanation:

-15 - 9y = 39

               39 + 15 = 54

-9y =54

y = 54 ÷ -9 = -6

y = -6

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True: A face of a polyhedron is simply a flat boundary that helps forms the 3D solid.
4 0
3 years ago
Which equation is equivalent to n + 4 = 11? *
dangina [55]

Answer:

(n + 4) *2 = 11 * 2

Step-by-step explanation:

(n + 4) *2 = 11 * 2

Divide both sides by 2

\frac{(n + 4) *2}{2} = \frac{11 * 2}{2}

n + 4 = 11

5 0
3 years ago
100 points gor correct answer Identify the base of a triangle in which h=(3x+15) ft and A=(15x+75) ft^2.
ivolga24 [154]

Answer:

b = 10

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height )

Here h = 3x + 15 and A = 15x + 75, thus

\frac{1}{2} × b × (3x + 15) = 15x + 75

Multiply both sides by 2 to clear the fraction

b(3x + 15) = 30x + 150

Divide both sides by (3x + 15)

b = \frac{30x+150}{3x+15} ← factor numerator and denominator

  = \frac{30(x + 5)}{3(x+5)} ← cancel the factor (x + 5) on numerator/denominator

  = \frac{30}{3}

  = 10

7 0
2 years ago
Read 2 more answers
I NEED HELP PLEASEE
xenn [34]

\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}

\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill

5 0
3 years ago
Which equation represents the polynomial function with zeros –3, 1, and 2, and a y-intercept of –12?
storchak [24]
To generate the equation we set up the factors
(x+3) * (x-1) * (x-2) which equals
x^2 + 2x -3 * (x-2)
x^3 +2x^2 -3x -2x^2 -4x +6  equals
x^3  -3x -4x +6 which equals

x^3  -7x +6


8 0
2 years ago
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